sneakypapi
07-29-2003, 11:19 PM
I have a question regarding ball in hand rules regarding 8 ball only. I am not sure if there is a major difference between APA and BCA rules.
Here is the situation:
Player A has the 8 ball remaining and is frozen to the rail with the 14 ball next to it (Player B's Ball of course).
Player B has given ball in hand for Player A to make his move. I know in APA rules Player A must make contact with the 8 ball then hit a rail after since the 8 ball in frozen and is called frozen.
Player A makes his move hitting directly to the 8 ball and cue goes straight back in slow roll and hits no rail after contact and the 8 stays frozen in position.
Player B calls this a foul like a scratch and says Player A loses the match, with much debate.
My question is this simply, fouling on the 8 ball is that the same as scratching or hitting the 8 ball in the wrong pocket, when calling the 8 ball is needed? Does Player A lose or does Player B just get ball in hand himself?
Here is the situation:
Player A has the 8 ball remaining and is frozen to the rail with the 14 ball next to it (Player B's Ball of course).
Player B has given ball in hand for Player A to make his move. I know in APA rules Player A must make contact with the 8 ball then hit a rail after since the 8 ball in frozen and is called frozen.
Player A makes his move hitting directly to the 8 ball and cue goes straight back in slow roll and hits no rail after contact and the 8 stays frozen in position.
Player B calls this a foul like a scratch and says Player A loses the match, with much debate.
My question is this simply, fouling on the 8 ball is that the same as scratching or hitting the 8 ball in the wrong pocket, when calling the 8 ball is needed? Does Player A lose or does Player B just get ball in hand himself?